What are the solutions to the equation x^2-3x-4=-x ?

The solutions to the equation x^2-3x-4=-x are x=1+sqrt(5),x=1-sqrt(5)

Find the zeros of x^2-3x-4=-x

The zeros of x^2-3x-4=-x are x=1+sqrt(5),x=1-sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 3 x - 4 = - x

x = 1 + 5, x = 1 - 5

Decimal Notation

x = 3.23606 \dots, x = - 1.23606 \dots

Solution steps

x^{2} - 3 x - 4 = - x

Move

x

to the left side

x^{2} - 2 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 4) = 25

x_{1, 2} = \frac{- ( - 2 ) \pm 2 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 5}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 5}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 5}{2 \cdot 1} : 1 + 5

x = \frac{- ( - 2 ) - 2 5}{2 \cdot 1} : 1 - 5

The solutions to the quadratic equation are:

x = 1 + 5, x = 1 - 5

2 x^{(2)} - x - 28 = 0

c (x) = 1500 + 5 x + 0.01 x^{2}

x^{2} + c x + b = 0

x, lo g_{10} (5) x^{2} - lo g_{10} (5 y) = 1

32 y^{2} + 32 y + 8 = 0

What are the solutions to the equation x^2-3x-4=-x ?
The solutions to the equation x^2-3x-4=-x are x=1+sqrt(5),x=1-sqrt(5)
Find the zeros of x^2-3x-4=-x
The zeros of x^2-3x-4=-x are x=1+sqrt(5),x=1-sqrt(5)