What are the solutions to the equation 10x^2+260x-23800=0 ?

The solutions to the equation 10x^2+260x-23800=0 are x=-13+sqrt(2549),x=-13-sqrt(2549)

Find the zeros of 10x^2+260x-23800=0

The zeros of 10x^2+260x-23800=0 are x=-13+sqrt(2549),x=-13-sqrt(2549)

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10 x^{2} + 260 x - 23800 = 0

x = - 13 + 2549, x = - 13 - 2549

Decimal Notation

x = 37.48762 \dots, x = - 63.48762 \dots

Solution steps

10 x^{2} + 260 x - 23800 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 260 \pm 26 0 ^{2} - 4 \cdot 10 ( - 23800 )}{2 \cdot 10}

26 0^{2} - 4 \cdot 10 (- 23800) = 202549

x_{1, 2} = \frac{- 260 \pm 20 2549}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 260 + 20 2549}{2 \cdot 10}, x_{2} = \frac{- 260 - 20 2549}{2 \cdot 10}

x = \frac{- 260 + 20 2549}{2 \cdot 10} : - 13 + 2549

x = \frac{- 260 - 20 2549}{2 \cdot 10} : - 13 - 2549

The solutions to the quadratic equation are:

x = - 13 + 2549, x = - 13 - 2549

2 x^{2} - 3 x = 44

4 m^{2} - 2 m - 6 = 0

d, h = - 0.001 (d - 20)^{2} + 6

2 x^{2} - 3 x = - 4

2 x^{2} - 3 x = - 7

What are the solutions to the equation 10x^2+260x-23800=0 ?
The solutions to the equation 10x^2+260x-23800=0 are x=-13+sqrt(2549),x=-13-sqrt(2549)
Find the zeros of 10x^2+260x-23800=0
The zeros of 10x^2+260x-23800=0 are x=-13+sqrt(2549),x=-13-sqrt(2549)