What are the solutions to the equation -21x^2+31x+26=0 ?

The solutions to the equation -21x^2+31x+26=0 are x=-(-31+sqrt(3145))/(42),x=(31+sqrt(3145))/(42)

Find the zeros of -21x^2+31x+26=0

The zeros of -21x^2+31x+26=0 are x=-(-31+sqrt(3145))/(42),x=(31+sqrt(3145))/(42)

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- 21 x^{2} + 31 x + 26 = 0

x = - \frac{- 31 + 3145}{42}, x = \frac{31 + 3145}{42}

Decimal Notation

x = - 0.59714 \dots, x = 2.07334 \dots

Solution steps

- 21 x^{2} + 31 x + 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 31 \pm 3 1 ^{2} - 4 ( - 21 ) \cdot 26}{2 ( - 21 )}

3 1^{2} - 4 (- 21) \cdot 26 = 3145

x_{1, 2} = \frac{- 31 \pm 3145}{2 ( - 21 )}

Separate the solutions

x_{1} = \frac{- 31 + 3145}{2 ( - 21 )}, x_{2} = \frac{- 31 - 3145}{2 ( - 21 )}

x = \frac{- 31 + 3145}{2 ( - 21 )} : - \frac{- 31 + 3145}{42}

x = \frac{- 31 - 3145}{2 ( - 21 )} : \frac{31 + 3145}{42}

The solutions to the quadratic equation are:

x = - \frac{- 31 + 3145}{42}, x = \frac{31 + 3145}{42}

6 x^{2} + 240 = 0

2 0^{2} + 15 6^{2} = x^{2}

4 x^{2} - 6 = - 12 x

x^{2} - 2 x = - 3

3 x^{2} - x = 30

What are the solutions to the equation -21x^2+31x+26=0 ?
The solutions to the equation -21x^2+31x+26=0 are x=-(-31+sqrt(3145))/(42),x=(31+sqrt(3145))/(42)
Find the zeros of -21x^2+31x+26=0
The zeros of -21x^2+31x+26=0 are x=-(-31+sqrt(3145))/(42),x=(31+sqrt(3145))/(42)