What are the solutions to the equation 3x^2+1/3 =2x ?

The solutions to the equation 3x^2+1/3 =2x are x= 1/3

Find the zeros of 3x^2+1/3 =2x

The zeros of 3x^2+1/3 =2x are x= 1/3

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3 x^{2} + \frac{1}{3} = 2 x

x = \frac{1}{3}

Decimal Notation

x = 0.33333 \dots

Solution steps

3 x^{2} + \frac{1}{3} = 2 x

Multiply both sides by

3

9 x^{2} + 1 = 6 x

Move

6 x

to the left side

9 x^{2} + 1 - 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

9 x^{2} - 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

(- 6)^{2} - 4 \cdot 9 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 9}

x = \frac{- ( - 6 )}{2 \cdot 9}

\frac{- ( - 6 )}{2 \cdot 9} = \frac{1}{3}

x = \frac{1}{3}

The solution to the quadratic equation is:

x = \frac{1}{3}

x^{2} + 15 x = 5 x

x^{2} - 2 x = 19

x^{2} - 2 x = 27

y, \frac{y ^{2}}{2} - a y = t + c

x^{2} + \frac{9 x}{2} - \frac{5}{2} = 0

What are the solutions to the equation 3x^2+1/3 =2x ?
The solutions to the equation 3x^2+1/3 =2x are x= 1/3
Find the zeros of 3x^2+1/3 =2x
The zeros of 3x^2+1/3 =2x are x= 1/3