What are the solutions to the equation -4x^2-4=8x ?

The solutions to the equation -4x^2-4=8x are x=-1

Find the zeros of -4x^2-4=8x

The zeros of -4x^2-4=8x are x=-1

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- 4 x^{2} - 4 = 8 x

x = - 1

Solution steps

- 4 x^{2} - 4 = 8 x

Move

8 x

to the left side

- 4 x^{2} - 4 - 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 4 x^{2} - 8 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 4 ) ( - 4 )}{2 ( - 4 )}

(- 8)^{2} - 4 (- 4) (- 4) = 0

x_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 ( - 4 )}

x = \frac{- ( - 8 )}{2 ( - 4 )}

\frac{- ( - 8 )}{2 ( - 4 )} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

x^{2} - 8 x = 0

8 x^{2} - 10 x = - 9

2 x^{2} + x - 4 = 0, x^{2} + x = 0

3 x^{2} - 72 x + 324 = 0

q, (\frac{1}{2} q^{2} + 20) x = (86 - 6 q - 3 q^{2}) x

What are the solutions to the equation -4x^2-4=8x ?
The solutions to the equation -4x^2-4=8x are x=-1
Find the zeros of -4x^2-4=8x
The zeros of -4x^2-4=8x are x=-1