What are the solutions to the equation (x+20)*(x-20)=3200 ?

The solutions to the equation (x+20)*(x-20)=3200 are x=60,x=-60

Find the zeros of (x+20)*(x-20)=3200

The zeros of (x+20)*(x-20)=3200 are x=60,x=-60

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(x + 20) \cdot (x - 20) = 3200

x = 60, x = - 60

Solution steps

(x + 20) (x - 20) = 3200

Expand

(x + 20) (x - 20) : x^{2} - 400

x^{2} - 400 = 3200

Move

3200

to the left side

x^{2} - 3600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot ( - 3600 )}{2 \cdot 1}

0^{2} - 4 \cdot 1 \cdot (- 3600) = 120

x_{1, 2} = \frac{- 0 \pm 120}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 0 + 120}{2 \cdot 1}, x_{2} = \frac{- 0 - 120}{2 \cdot 1}

x = \frac{- 0 + 120}{2 \cdot 1} : 60

x = \frac{- 0 - 120}{2 \cdot 1} : - 60

The solutions to the quadratic equation are:

x = 60, x = - 60

x, p = 3 x^{2} y^{3} z

2 x^{2} = 1 - 2 x

- 2 x^{2} + 120 x + 500 = 0

x = 3 x - x^{2}

6 x^{2} - 48 = 0

What are the solutions to the equation (x+20)*(x-20)=3200 ?
The solutions to the equation (x+20)*(x-20)=3200 are x=60,x=-60
Find the zeros of (x+20)*(x-20)=3200
The zeros of (x+20)*(x-20)=3200 are x=60,x=-60