What are the solutions to the equation 5p^2-5=2p ?

The solutions to the equation 5p^2-5=2p are p=(1+sqrt(26))/5 ,p=(1-sqrt(26))/5

Find the zeros of 5p^2-5=2p

The zeros of 5p^2-5=2p are p=(1+sqrt(26))/5 ,p=(1-sqrt(26))/5

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5 p^{2} - 5 = 2 p

p = \frac{1 + 26}{5}, p = \frac{1 - 26}{5}

Decimal Notation

p = 1.21980 \dots, p = - 0.81980 \dots

Solution steps

5 p^{2} - 5 = 2 p

Move

2 p

to the left side

5 p^{2} - 5 - 2 p = 0

Write in the standard form

a x^{2} + b x + c = 0

5 p^{2} - 2 p - 5 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 5 ( - 5 )}{2 \cdot 5}

(- 2)^{2} - 4 \cdot 5 (- 5) = 226

p_{1, 2} = \frac{- ( - 2 ) \pm 2 26}{2 \cdot 5}

Separate the solutions

p_{1} = \frac{- ( - 2 ) + 2 26}{2 \cdot 5}, p_{2} = \frac{- ( - 2 ) - 2 26}{2 \cdot 5}

p = \frac{- ( - 2 ) + 2 26}{2 \cdot 5} : \frac{1 + 26}{5}

p = \frac{- ( - 2 ) - 2 26}{2 \cdot 5} : \frac{1 - 26}{5}

The solutions to the quadratic equation are:

p = \frac{1 + 26}{5}, p = \frac{1 - 26}{5}

x, F = x + (x^{2} + x y + 1) y

x^{2} = - 112

n^{2} = - 43

x^{2} - 8 x - 9 = 0

2 x^{2} - 8 x - 2 = - 8

What are the solutions to the equation 5p^2-5=2p ?
The solutions to the equation 5p^2-5=2p are p=(1+sqrt(26))/5 ,p=(1-sqrt(26))/5
Find the zeros of 5p^2-5=2p
The zeros of 5p^2-5=2p are p=(1+sqrt(26))/5 ,p=(1-sqrt(26))/5