What are the solutions to the equation 2x-3+x^2=0 ?

The solutions to the equation 2x-3+x^2=0 are x=1,x=-3

Find the zeros of 2x-3+x^2=0

The zeros of 2x-3+x^2=0 are x=1,x=-3

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2 x - 3 + x^{2} = 0

x = 1, x = - 3

Solution steps

2 x - 3 + x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 3) = 4

x_{1, 2} = \frac{- 2 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4}{2 \cdot 1}, x_{2} = \frac{- 2 - 4}{2 \cdot 1}

x = \frac{- 2 + 4}{2 \cdot 1} : 1

x = \frac{- 2 - 4}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 1, x = - 3

x, x^{2} + y^{2} + 7 x + 7 y + 48 = 0

2 x^{2} - 30 = 7 x

6 x^{2} - 23 x - 35 = 0

x \frac{x}{5} + 4 x = \frac{1}{2}

y, x^{3} + y^{2} + 2 x = 6

What are the solutions to the equation 2x-3+x^2=0 ?
The solutions to the equation 2x-3+x^2=0 are x=1,x=-3
Find the zeros of 2x-3+x^2=0
The zeros of 2x-3+x^2=0 are x=1,x=-3