What are the solutions to the equation (2pi)/3 (9r-32)r=0 ?

The solutions to the equation (2pi)/3 (9r-32)r=0 are r= 32/9 ,r=0

Find the zeros of (2pi)/3 (9r-32)r=0

The zeros of (2pi)/3 (9r-32)r=0 are r= 32/9 ,r=0

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\frac{2 π}{3} (9 r - 32) r = 0

r = \frac{32}{9}, r = 0

Decimal Notation

r = 3.55555 \dots, r = 0

Solution steps

\frac{2 π}{3} (9 r - 32) r = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

9 r - 32 = 0 or r = 0

Solve

9 r - 32 = 0 : r = \frac{32}{9}

The solutions to the quadratic equation are:

r = \frac{32}{9}, r = 0

4 (3 x^{2} - 4) = 0

(0.63024) = \frac{1}{2} (10.9) (x)^{2}

49 y^{2} = 121

2 x^{2} + 6 x - 80 = 0

6 x^{2} - 7 x - 13 = 0

What are the solutions to the equation (2pi)/3 (9r-32)r=0 ?
The solutions to the equation (2pi)/3 (9r-32)r=0 are r= 32/9 ,r=0
Find the zeros of (2pi)/3 (9r-32)r=0
The zeros of (2pi)/3 (9r-32)r=0 are r= 32/9 ,r=0