What are the solutions to the equation 2x^2-13x-10=0 ?

The solutions to the equation 2x^2-13x-10=0 are x=(13+sqrt(249))/4 ,x=(13-sqrt(249))/4

Find the zeros of 2x^2-13x-10=0

The zeros of 2x^2-13x-10=0 are x=(13+sqrt(249))/4 ,x=(13-sqrt(249))/4

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2 x^{2} - 13 x - 10 = 0

x = \frac{13 + 249}{4}, x = \frac{13 - 249}{4}

Decimal Notation

x = 7.19493 \dots, x = - 0.69493 \dots

Solution steps

2 x^{2} - 13 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

(- 13)^{2} - 4 \cdot 2 (- 10) = 249

x_{1, 2} = \frac{- ( - 13 ) \pm 249}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 249}{2 \cdot 2}, x_{2} = \frac{- ( - 13 ) - 249}{2 \cdot 2}

x = \frac{- ( - 13 ) + 249}{2 \cdot 2} : \frac{13 + 249}{4}

x = \frac{- ( - 13 ) - 249}{2 \cdot 2} : \frac{13 - 249}{4}

The solutions to the quadratic equation are:

x = \frac{13 + 249}{4}, x = \frac{13 - 249}{4}

8 x^{2} + 26 x - 24 = 0

- 2 x^{2} - 196 = 0

2 x^{2} - 4 x + 2 = 2

(x + \frac{1}{2}) (\frac{3}{2} x - 1) = 0

x^{2} - x - (- 1) = 0

What are the solutions to the equation 2x^2-13x-10=0 ?
The solutions to the equation 2x^2-13x-10=0 are x=(13+sqrt(249))/4 ,x=(13-sqrt(249))/4
Find the zeros of 2x^2-13x-10=0
The zeros of 2x^2-13x-10=0 are x=(13+sqrt(249))/4 ,x=(13-sqrt(249))/4