What are the solutions to the equation -2x^2-196=0 ?

The solutions to the equation -2x^2-196=0 are x=sqrt(2)*7i,x=-sqrt(2)*7i

Find the zeros of -2x^2-196=0

The zeros of -2x^2-196=0 are x=sqrt(2)*7i,x=-sqrt(2)*7i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} - 196 = 0

x = 2 \cdot 7 i, x = - 2 \cdot 7 i

Solution steps

- 2 x^{2} - 196 = 0

Move

196

to the right side

- 2 x^{2} = 196

Divide both sides by

- 2

x^{2} = - 98

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 98, x = - - 98

- 98 = 2 \cdot 7 i

- - 98 = - 2 \cdot 7 i

x = 2 \cdot 7 i, x = - 2 \cdot 7 i

2 x^{2} - 4 x + 2 = 2

(x + \frac{1}{2}) (\frac{3}{2} x - 1) = 0

x^{2} - x - (- 1) = 0

y, x = 6 - y^{2} - z^{2}

3 a^{2} - 2 a - 1 = 0

What are the solutions to the equation -2x^2-196=0 ?
The solutions to the equation -2x^2-196=0 are x=sqrt(2)*7i,x=-sqrt(2)*7i
Find the zeros of -2x^2-196=0
The zeros of -2x^2-196=0 are x=sqrt(2)*7i,x=-sqrt(2)*7i