What are the solutions to the equation solvefor x,3x^2-2x+1=0 ?

The solutions to the equation solvefor x,3x^2-2x+1=0 are x= 1/3+i(sqrt(2))/3 ,x= 1/3-i(sqrt(2))/3

Find the zeros of solvefor x,3x^2-2x+1=0

The zeros of solvefor x,3x^2-2x+1=0 are x= 1/3+i(sqrt(2))/3 ,x= 1/3-i(sqrt(2))/3

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x, 3 x^{2} - 2 x + 1 = 0

x = \frac{1}{3} + i \frac{2}{3}, x = \frac{1}{3} - i \frac{2}{3}

Solution steps

3 x^{2} - 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 \cdot 1}{2 \cdot 3}

Simplify

(- 2)^{2} - 4 \cdot 3 \cdot 1 : 22 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 2 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 2 i}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 2 2 i}{2 \cdot 3}

x = \frac{- ( - 2 ) + 2 2 i}{2 \cdot 3} : \frac{1}{3} + i \frac{2}{3}

x = \frac{- ( - 2 ) - 2 2 i}{2 \cdot 3} : \frac{1}{3} - i \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3} + i \frac{2}{3}, x = \frac{1}{3} - i \frac{2}{3}

- x^{2} - 7 x - 2 = 0

c^{2} = c + 1

X^{2} + 11 X + 18 = 0

x^{2} - 8 x - 17 = 0

5 x^{2} - 10 x - 12 = 0

What are the solutions to the equation solvefor x,3x^2-2x+1=0 ?
The solutions to the equation solvefor x,3x^2-2x+1=0 are x= 1/3+i(sqrt(2))/3 ,x= 1/3-i(sqrt(2))/3
Find the zeros of solvefor x,3x^2-2x+1=0
The zeros of solvefor x,3x^2-2x+1=0 are x= 1/3+i(sqrt(2))/3 ,x= 1/3-i(sqrt(2))/3