What are the solutions to the equation (x^2)/2-23=-x+1 ?

The solutions to the equation (x^2)/2-23=-x+1 are x=6,x=-8

Find the zeros of (x^2)/2-23=-x+1

The zeros of (x^2)/2-23=-x+1 are x=6,x=-8

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\frac{x ^{2}}{2} - 23 = - x + 1

x = 6, x = - 8

Solution steps

\frac{x ^{2}}{2} - 23 = - x + 1

Multiply both sides by

2

x^{2} - 46 = - 2 x + 2

Move

2

to the left side

x^{2} - 48 = - 2 x

Move

2 x

to the left side

x^{2} - 48 + 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 2 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 48 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 48) = 14

x_{1, 2} = \frac{- 2 \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 14}{2 \cdot 1}, x_{2} = \frac{- 2 - 14}{2 \cdot 1}

x = \frac{- 2 + 14}{2 \cdot 1} : 6

x = \frac{- 2 - 14}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 6, x = - 8

x, (x^{2} + 4) y + x y = 4 x

x, 3 x^{2} - 4 x y + 4 y^{2} + 8 x - 1 = 0

4 x^{2} - 21 x + 20 = 0

x, 0 = \frac{1}{2} (x^{2} + y^{2})

- 5 x^{2} - 20 x = 0

What are the solutions to the equation (x^2)/2-23=-x+1 ?
The solutions to the equation (x^2)/2-23=-x+1 are x=6,x=-8
Find the zeros of (x^2)/2-23=-x+1
The zeros of (x^2)/2-23=-x+1 are x=6,x=-8