What are the solutions to the equation (4q+3)(q+2)=0 ?

The solutions to the equation (4q+3)(q+2)=0 are q=-3/4 ,q=-2

Find the zeros of (4q+3)(q+2)=0

The zeros of (4q+3)(q+2)=0 are q=-3/4 ,q=-2

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(4 q + 3) (q + 2) = 0

q = - \frac{3}{4}, q = - 2

Decimal Notation

q = - 0.75, q = - 2

Solution steps

(4 q + 3) (q + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 q + 3 = 0 or q + 2 = 0

Solve

4 q + 3 = 0 : q = - \frac{3}{4}

Solve

q + 2 = 0 : q = - 2

The solutions to the quadratic equation are:

q = - \frac{3}{4}, q = - 2

a - a^{2}

2 x^{2} - x = 8 x + 4

4. 9^{2}

x + 8 \geq 5

\frac{2 x - 1}{x + 1} \leq 1

What are the solutions to the equation (4q+3)(q+2)=0 ?
The solutions to the equation (4q+3)(q+2)=0 are q=-3/4 ,q=-2
Find the zeros of (4q+3)(q+2)=0
The zeros of (4q+3)(q+2)=0 are q=-3/4 ,q=-2