What are the solutions to the equation factor 5x^2+28x-12=0 ?

The solutions to the equation factor 5x^2+28x-12=0 are x= 2/5 ,x=-6

Find the zeros of factor 5x^2+28x-12=0

The zeros of factor 5x^2+28x-12=0 are x= 2/5 ,x=-6

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5 x^{2} + 28 x - 12 = 0

x = \frac{2}{5}, x = - 6

Decimal Notation

x = 0.4, x = - 6

Solution steps

5 x^{2} + 28 x - 12 = 0

Factor

5 x^{2} + 28 x - 12 : (5 x - 2) (x + 6)

(5 x - 2) (x + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x - 2 = 0 or x + 6 = 0

Solve

5 x - 2 = 0 : x = \frac{2}{5}

Solve

x + 6 = 0 : x = - 6

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = - 6

(x - 2)^{2} + 1 = 0

(x - 2)^{2} + 1 = 5

8 x^{2} - 37 x - 15 = 0

x^{2} - 14 x + 28 = 0

X^{2} + 24 X - 340 = 0

What are the solutions to the equation factor 5x^2+28x-12=0 ?
The solutions to the equation factor 5x^2+28x-12=0 are x= 2/5 ,x=-6
Find the zeros of factor 5x^2+28x-12=0
The zeros of factor 5x^2+28x-12=0 are x= 2/5 ,x=-6