What are the solutions to the equation x=x^2-24x+144 ?

The solutions to the equation x=x^2-24x+144 are x=16,x=9

Find the zeros of x=x^2-24x+144

The zeros of x=x^2-24x+144 are x=16,x=9

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x = x^{2} - 24 x + 144

x = 16, x = 9

Solution steps

x = x^{2} - 24 x + 144

Switch sides

x^{2} - 24 x + 144 = x

Move

x

to the left side

x^{2} - 25 x + 144 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 1 \cdot 144}{2 \cdot 1}

(- 25)^{2} - 4 \cdot 1 \cdot 144 = 7

x_{1, 2} = \frac{- ( - 25 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 25 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 25 ) - 7}{2 \cdot 1}

x = \frac{- ( - 25 ) + 7}{2 \cdot 1} : 16

x = \frac{- ( - 25 ) - 7}{2 \cdot 1} : 9

The solutions to the quadratic equation are:

x = 16, x = 9

4 x + \frac{2}{3} x^{2} - 1 = 0

(1 - x^{2}) \cdot (- 3 - x^{3} - 2) = 0

a^{2} + 1 0^{2} = 1 6^{2}

10 x^{2} + 1 = 0

21 - 2 x^{2} = - 51

What are the solutions to the equation x=x^2-24x+144 ?
The solutions to the equation x=x^2-24x+144 are x=16,x=9
Find the zeros of x=x^2-24x+144
The zeros of x=x^2-24x+144 are x=16,x=9