What are the solutions to the equation 2+24.5x-4.9x^2=0 ?

The solutions to the equation 2+24.5x-4.9x^2=0 are x=-(-35+3sqrt(145))/(14),x=(35+3sqrt(145))/(14)

Find the zeros of 2+24.5x-4.9x^2=0

The zeros of 2+24.5x-4.9x^2=0 are x=-(-35+3sqrt(145))/(14),x=(35+3sqrt(145))/(14)

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2 + 24.5 x - 4.9 x^{2} = 0

x = - \frac{- 35 + 3 145}{14}, x = \frac{35 + 3 145}{14}

Decimal Notation

x = - 0.08034 \dots, x = 5.08034 \dots

Solution steps

2 + 24.5 x - 4.9 x^{2} = 0

Multiply both sides by

10

20 + 245 x - 49 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 49 x^{2} + 245 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 245 \pm 24 5 ^{2} - 4 ( - 49 ) \cdot 20}{2 ( - 49 )}

24 5^{2} - 4 (- 49) \cdot 20 = 21145

x_{1, 2} = \frac{- 245 \pm 21 145}{2 ( - 49 )}

Separate the solutions

x_{1} = \frac{- 245 + 21 145}{2 ( - 49 )}, x_{2} = \frac{- 245 - 21 145}{2 ( - 49 )}

x = \frac{- 245 + 21 145}{2 ( - 49 )} : - \frac{- 35 + 3 145}{14}

x = \frac{- 245 - 21 145}{2 ( - 49 )} : \frac{35 + 3 145}{14}

The solutions to the quadratic equation are:

x = - \frac{- 35 + 3 145}{14}, x = \frac{35 + 3 145}{14}

x, x^{2} - x y + y^{2} = 19

x^{2} - 35 x = 0

s^{2} = \frac{400}{3}

y, x^{3} + 2 y^{2} - x y = 2

2 t^{2} + 3 t - 6 = 0

What are the solutions to the equation 2+24.5x-4.9x^2=0 ?
The solutions to the equation 2+24.5x-4.9x^2=0 are x=-(-35+3sqrt(145))/(14),x=(35+3sqrt(145))/(14)
Find the zeros of 2+24.5x-4.9x^2=0
The zeros of 2+24.5x-4.9x^2=0 are x=-(-35+3sqrt(145))/(14),x=(35+3sqrt(145))/(14)