What are the solutions to the equation p^2+16p+63=0 ?

The solutions to the equation p^2+16p+63=0 are p=-7,p=-9

Find the zeros of p^2+16p+63=0

The zeros of p^2+16p+63=0 are p=-7,p=-9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

p^{2} + 16 p + 63 = 0

p = - 7, p = - 9

Solution steps

p^{2} + 16 p + 63 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 63}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 63 = 2

p_{1, 2} = \frac{- 16 \pm 2}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 16 + 2}{2 \cdot 1}, p_{2} = \frac{- 16 - 2}{2 \cdot 1}

p = \frac{- 16 + 2}{2 \cdot 1} : - 7

p = \frac{- 16 - 2}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

p = - 7, p = - 9

x^{2} - 10 = 1

z^{2} + 8 z + 20 = 0

464 - 180 x + 12 x^{2} = 0

x^{2} + (x + 5)^{2} = (x + 10)^{2}

1.5 X^{2} + 2 X = 0

What are the solutions to the equation p^2+16p+63=0 ?
The solutions to the equation p^2+16p+63=0 are p=-7,p=-9
Find the zeros of p^2+16p+63=0
The zeros of p^2+16p+63=0 are p=-7,p=-9