What are the solutions to the equation 0=32x-16x^2 ?

The solutions to the equation 0=32x-16x^2 are x=0,x=2

Find the zeros of 0=32x-16x^2

The zeros of 0=32x-16x^2 are x=0,x=2

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0 = 32 x - 16 x^{2}

x = 0, x = 2

Solution steps

0 = 32 x - 16 x^{2}

Switch sides

32 x - 16 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 x^{2} + 32 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

3 2^{2} - 4 (- 16) \cdot 0 = 32

x_{1, 2} = \frac{- 32 \pm 32}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 32 + 32}{2 ( - 16 )}, x_{2} = \frac{- 32 - 32}{2 ( - 16 )}

x = \frac{- 32 + 32}{2 ( - 16 )} : 0

x = \frac{- 32 - 32}{2 ( - 16 )} : 2

The solutions to the quadratic equation are:

x = 0, x = 2

(3 - x) (3 - x) - 1 = 0

- x^{2} + 4 x - 9

- x^{2} + 4 x - 5

- x^{2} + 4 x + 1

5 u^{2} + 20 u = 0

What are the solutions to the equation 0=32x-16x^2 ?
The solutions to the equation 0=32x-16x^2 are x=0,x=2
Find the zeros of 0=32x-16x^2
The zeros of 0=32x-16x^2 are x=0,x=2