What are the solutions to the equation x(x-1)+2(x-2)=-2 ?

The solutions to the equation x(x-1)+2(x-2)=-2 are x=1,x=-2

Find the zeros of x(x-1)+2(x-2)=-2

The zeros of x(x-1)+2(x-2)=-2 are x=1,x=-2

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x (x - 1) + 2 (x - 2) = - 2

x = 1, x = - 2

Solution steps

x (x - 1) + 2 (x - 2) = - 2

Expand

x (x - 1) + 2 (x - 2) : x^{2} + x - 4

x^{2} + x - 4 = - 2

Move

2

to the left side

x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 2) = 3

x_{1, 2} = \frac{- 1 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 3}{2 \cdot 1}, x_{2} = \frac{- 1 - 3}{2 \cdot 1}

x = \frac{- 1 + 3}{2 \cdot 1} : 1

x = \frac{- 1 - 3}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 1, x = - 2

12 a^{2} + 36 a = 0

v^{2} - 81 = 0

r, r^{2} + r - 42 = 0

x, x^{2} - 12 x + 27 = 0

x^{2} - 9 x - 10 = 2 x + 10

What are the solutions to the equation x(x-1)+2(x-2)=-2 ?
The solutions to the equation x(x-1)+2(x-2)=-2 are x=1,x=-2
Find the zeros of x(x-1)+2(x-2)=-2
The zeros of x(x-1)+2(x-2)=-2 are x=1,x=-2