What are the solutions to the equation n^2+3n=40 ?

The solutions to the equation n^2+3n=40 are n=5,n=-8

Find the zeros of n^2+3n=40

The zeros of n^2+3n=40 are n=5,n=-8

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n^{2} + 3 n = 40

n = 5, n = - 8

Solution steps

n^{2} + 3 n = 40

Move

40

to the left side

n^{2} + 3 n - 40 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 40) = 13

n_{1, 2} = \frac{- 3 \pm 13}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 3 + 13}{2 \cdot 1}, n_{2} = \frac{- 3 - 13}{2 \cdot 1}

n = \frac{- 3 + 13}{2 \cdot 1} : 5

n = \frac{- 3 - 13}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

n = 5, n = - 8

6 x^{2} - 150 x + 396 = 0

35 b^{2} - 8 = 6 b

(x - 3)^{2} = 2 (17 - 3 x)

144 z^{2} - 168 z + 49 = 0

(u)^{2} - 2 u - 15 = 0

What are the solutions to the equation n^2+3n=40 ?
The solutions to the equation n^2+3n=40 are n=5,n=-8
Find the zeros of n^2+3n=40
The zeros of n^2+3n=40 are n=5,n=-8