What is the answer to |x+1|=x^2-11 ?

The answer to |x+1|=x^2-11 is x=(-1-sqrt(41))/2 \lor x=4

Solve for x: |x+1|=x^2-11

The solution is x=(-1-sqrt(41))/2 \lor x=4

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∣ x + 1 ∣ = x^{2} - 11

x = \frac{- 1 - 41}{2} or x = 4

Decimal Notation

x = - 3.70156 \dots, x = 4

Solution steps

∣ x + 1 ∣ = x^{2} - 11

Find positive and negative intervals

x < - 1, x \geq - 1

Solve the inequality for each interval

x = \frac{- 1 - 41}{2} or x = 4

\frac{58}{18} \cdot \frac{9}{26}

\frac{1 + 2 i}{5 - 3 i}

4 x^{2} - 4 x = - 4 x + 1

\frac{35}{x + 5} \leq 7

\frac{12 x ^{3}}{9 y ^{8}}

What is the answer to |x+1|=x^2-11 ?
The answer to |x+1|=x^2-11 is x=(-1-sqrt(41))/2 \lor x=4
Solve for x: |x+1|=x^2-11
The solution is x=(-1-sqrt(41))/2 \lor x=4