What are the solutions to the equation t^2-3t-40=0 ?

The solutions to the equation t^2-3t-40=0 are t=8,t=-5

Find the zeros of t^2-3t-40=0

The zeros of t^2-3t-40=0 are t=8,t=-5

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t^{2} - 3 t - 40 = 0

t = 8, t = - 5

Solution steps

t^{2} - 3 t - 40 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 40) = 13

t_{1, 2} = \frac{- ( - 3 ) \pm 13}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 3 ) + 13}{2 \cdot 1}, t_{2} = \frac{- ( - 3 ) - 13}{2 \cdot 1}

t = \frac{- ( - 3 ) + 13}{2 \cdot 1} : 8

t = \frac{- ( - 3 ) - 13}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

t = 8, t = - 5

4 x^{2} - 3 x + 8 = 0

6 x^{2} = - 3 x + 1

8 v^{2} + 14 + 5 v = - v^{2} + 5 v

3 t^{2} - t - 3 = 0

x^{2} - 14 x + 34 = 0

What are the solutions to the equation t^2-3t-40=0 ?
The solutions to the equation t^2-3t-40=0 are t=8,t=-5
Find the zeros of t^2-3t-40=0
The zeros of t^2-3t-40=0 are t=8,t=-5