What are the solutions to the equation m^2+1.25m=0 ?

The solutions to the equation m^2+1.25m=0 are m=0,m=-1.25

Find the zeros of m^2+1.25m=0

The zeros of m^2+1.25m=0 are m=0,m=-1.25

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m^{2} + 1.25 m = 0

m = 0, m = - 1.25

Solution steps

m^{2} + 1.25 m = 0

Factor

m^{2} + 1.25 m : m (m + 1.25)

m (m + 1.25) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

m = 0 or m + 1.25 = 0

Solve

m + 1.25 = 0 : m = - 1.25

The solutions to the quadratic equation are:

m = 0, m = - 1.25

3 t^{2} + 6 t = 0

s^{2} - 12 s + 61

8 x^{2} - 18 x = - 8

20 = - 1.9 t^{2} + 18 t + 1

x - 2 = 10 - x^{2}

What are the solutions to the equation m^2+1.25m=0 ?
The solutions to the equation m^2+1.25m=0 are m=0,m=-1.25
Find the zeros of m^2+1.25m=0
The zeros of m^2+1.25m=0 are m=0,m=-1.25