What are the solutions to the equation completesquare x^2-0.4x-1.2=0 ?

The solutions to the equation completesquare x^2-0.4x-1.2=0 are x=(sqrt(31)+1)/5 ,x=(-sqrt(31)+1)/5

Find the zeros of completesquare x^2-0.4x-1.2=0

The zeros of completesquare x^2-0.4x-1.2=0 are x=(sqrt(31)+1)/5 ,x=(-sqrt(31)+1)/5

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x^{2} - 0.4 x - 1.2 = 0

x = \frac{31 + 1}{5}, x = \frac{- 31 + 1}{5}

Decimal Notation

x = 1.31355 \dots, x = - 0.91355 \dots

Solution steps

x^{2} - 0.4 x - 1.2 = 0

Multiply both sides by

10

10 x^{2} - 4 x - 12 = 0

Move

12

to the right side

10 x^{2} - 4 x = 12

Divide both sides by

10

\frac{10 x ^{2} - 4 x}{10} = \frac{12}{10}

x^{2} - \frac{2 x}{5} = \frac{6}{5}

Rewrite in the form

(x + a)^{2} = b

(x - \frac{1}{5})^{2} = \frac{31}{25}

For

the solutions are

f (x) = a, - a

Solve

x - \frac{1}{5} = \frac{31}{25} : x = \frac{31 + 1}{5}

Solve

x - \frac{1}{5} = - \frac{31}{25} : x = \frac{- 31 + 1}{5}

The solutions to the quadratic equation are:

x = \frac{31 + 1}{5}, x = \frac{- 31 + 1}{5}

2 x (x + 5) = 45

D, (x^{2} D^{2} - 4 x D - 6 I) y = 0

(x - 2)^{2} = 8 (x - 2)

x^{2} + 5 x = 50

3 x^{2} + 52 x - 256 = 0

What are the solutions to the equation completesquare x^2-0.4x-1.2=0 ?
The solutions to the equation completesquare x^2-0.4x-1.2=0 are x=(sqrt(31)+1)/5 ,x=(-sqrt(31)+1)/5
Find the zeros of completesquare x^2-0.4x-1.2=0
The zeros of completesquare x^2-0.4x-1.2=0 are x=(sqrt(31)+1)/5 ,x=(-sqrt(31)+1)/5