What are the solutions to the equation 0=x^2-12x+24 ?

The solutions to the equation 0=x^2-12x+24 are x=2(3+sqrt(3)),x=2(3-sqrt(3))

Find the zeros of 0=x^2-12x+24

The zeros of 0=x^2-12x+24 are x=2(3+sqrt(3)),x=2(3-sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = x^{2} - 12 x + 24

x = 2 (3 + 3), x = 2 (3 - 3)

Decimal Notation

x = 9.46410 \dots, x = 2.53589 \dots

Solution steps

0 = x^{2} - 12 x + 24

Switch sides

x^{2} - 12 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 24 = 43

x_{1, 2} = \frac{- ( - 12 ) \pm 4 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 3}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 4 3}{2 \cdot 1}

x = \frac{- ( - 12 ) + 4 3}{2 \cdot 1} : 2 (3 + 3)

x = \frac{- ( - 12 ) - 4 3}{2 \cdot 1} : 2 (3 - 3)

The solutions to the quadratic equation are:

x = 2 (3 + 3), x = 2 (3 - 3)

9 = (x + 5)^{2}

0 = x^{2} - 12 x + 32

0 = 2 x^{2} - x - 10

x^{2} + 2.2 x - 10.35 = 0

x, f = 5 x^{2} + 6 y^{3} + 2 z^{4}

What are the solutions to the equation 0=x^2-12x+24 ?
The solutions to the equation 0=x^2-12x+24 are x=2(3+sqrt(3)),x=2(3-sqrt(3))
Find the zeros of 0=x^2-12x+24
The zeros of 0=x^2-12x+24 are x=2(3+sqrt(3)),x=2(3-sqrt(3))