What are the solutions to the equation x^2-(2x)/5-4=0 ?

The solutions to the equation x^2-(2x)/5-4=0 are x=(1+sqrt(101))/5 ,x=(1-sqrt(101))/5

Find the zeros of x^2-(2x)/5-4=0

The zeros of x^2-(2x)/5-4=0 are x=(1+sqrt(101))/5 ,x=(1-sqrt(101))/5

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x^{2} - \frac{2 x}{5} - 4 = 0

x = \frac{1 + 101}{5}, x = \frac{1 - 101}{5}

Decimal Notation

x = 2.20997 \dots, x = - 1.80997 \dots

Solution steps

x^{2} - \frac{2 x}{5} - 4 = 0

Multiply both sides by

5

5 x^{2} - 2 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 5 ( - 20 )}{2 \cdot 5}

(- 2)^{2} - 4 \cdot 5 (- 20) = 2101

x_{1, 2} = \frac{- ( - 2 ) \pm 2 101}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 101}{2 \cdot 5}, x_{2} = \frac{- ( - 2 ) - 2 101}{2 \cdot 5}

x = \frac{- ( - 2 ) + 2 101}{2 \cdot 5} : \frac{1 + 101}{5}

x = \frac{- ( - 2 ) - 2 101}{2 \cdot 5} : \frac{1 - 101}{5}

The solutions to the quadratic equation are:

x = \frac{1 + 101}{5}, x = \frac{1 - 101}{5}

(4 x - 40)^{2} = 48

3 π x - 1.1 x^{2} - λ x = 0

7 x - 3 x^{2} = 85 + 2 x^{2} + 2 x

3 x^{2} - 2 x = 7

x^{2} + 8 x + 43 = 0

What are the solutions to the equation x^2-(2x)/5-4=0 ?
The solutions to the equation x^2-(2x)/5-4=0 are x=(1+sqrt(101))/5 ,x=(1-sqrt(101))/5
Find the zeros of x^2-(2x)/5-4=0
The zeros of x^2-(2x)/5-4=0 are x=(1+sqrt(101))/5 ,x=(1-sqrt(101))/5