What are the solutions to the equation quadraticformula-x^2-4x-2=0 ?

The solutions to the equation quadraticformula-x^2-4x-2=0 are x=-2-sqrt(2),x=-2+sqrt(2)

Find the zeros of quadraticformula-x^2-4x-2=0

The zeros of quadraticformula-x^2-4x-2=0 are x=-2-sqrt(2),x=-2+sqrt(2)

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- x^{2} - 4 x - 2 = 0

x = - 2 - 2, x = - 2 + 2

Decimal Notation

x = - 3.41421 \dots, x = - 0.58578 \dots

Solution steps

- x^{2} - 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 1 ) ( - 2 )}{2 ( - 1 )}

(- 4)^{2} - 4 (- 1) (- 2) = 22

x_{1, 2} = \frac{- ( - 4 ) \pm 2 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 2}{2 ( - 1 )}, x_{2} = \frac{- ( - 4 ) - 2 2}{2 ( - 1 )}

x = \frac{- ( - 4 ) + 2 2}{2 ( - 1 )} : - 2 - 2

x = \frac{- ( - 4 ) - 2 2}{2 ( - 1 )} : - 2 + 2

The solutions to the quadratic equation are:

x = - 2 - 2, x = - 2 + 2

x, - 4 x^{2} - 4 x - 1 = 0

x, x^{2} + m x + 1 = m x^{2} + 2 x

w^{2} + w - 20 = 0

s^{2} + s - 4 = 0

x, 4 x^{2} - 1 = 0

What are the solutions to the equation quadraticformula-x^2-4x-2=0 ?
The solutions to the equation quadraticformula-x^2-4x-2=0 are x=-2-sqrt(2),x=-2+sqrt(2)
Find the zeros of quadraticformula-x^2-4x-2=0
The zeros of quadraticformula-x^2-4x-2=0 are x=-2-sqrt(2),x=-2+sqrt(2)