What are the solutions to the equation 3x^2-16x-5=0 ?

The solutions to the equation 3x^2-16x-5=0 are x=(8+sqrt(79))/3 ,x=(8-sqrt(79))/3

Find the zeros of 3x^2-16x-5=0

The zeros of 3x^2-16x-5=0 are x=(8+sqrt(79))/3 ,x=(8-sqrt(79))/3

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3 x^{2} - 16 x - 5 = 0

x = \frac{8 + 79}{3}, x = \frac{8 - 79}{3}

Decimal Notation

x = 5.62939 \dots, x = - 0.29606 \dots

Solution steps

3 x^{2} - 16 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

(- 16)^{2} - 4 \cdot 3 (- 5) = 279

x_{1, 2} = \frac{- ( - 16 ) \pm 2 79}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 79}{2 \cdot 3}, x_{2} = \frac{- ( - 16 ) - 2 79}{2 \cdot 3}

x = \frac{- ( - 16 ) + 2 79}{2 \cdot 3} : \frac{8 + 79}{3}

x = \frac{- ( - 16 ) - 2 79}{2 \cdot 3} : \frac{8 - 79}{3}

The solutions to the quadratic equation are:

x = \frac{8 + 79}{3}, x = \frac{8 - 79}{3}

x^{2} + 22 x + 121 = 0

d, d 3 z d θ 3 - 3 d 2 z d θ 2 + 2 d z d θ = e 3 θ 1 + e θ

20 t^{2} - 24 t + 65

4 X^{2} - 42 X = 7 X - 12

120 n^{2} - 328 n = - 224

What are the solutions to the equation 3x^2-16x-5=0 ?
The solutions to the equation 3x^2-16x-5=0 are x=(8+sqrt(79))/3 ,x=(8-sqrt(79))/3
Find the zeros of 3x^2-16x-5=0
The zeros of 3x^2-16x-5=0 are x=(8+sqrt(79))/3 ,x=(8-sqrt(79))/3