What are the solutions to the equation 12x-x^2=36 ?

The solutions to the equation 12x-x^2=36 are x=6

Find the zeros of 12x-x^2=36

The zeros of 12x-x^2=36 are x=6

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12 x - x^{2} = 36

x = 6

Solution steps

12 x - x^{2} = 36

Move

36

to the left side

12 x - x^{2} - 36 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 12 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 1 ) ( - 36 )}{2 ( - 1 )}

1 2^{2} - 4 (- 1) (- 36) = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 ( - 1 )}

x = \frac{- 12}{2 ( - 1 )}

\frac{- 12}{2 ( - 1 )} = 6

x = 6

The solution to the quadratic equation is:

x = 6

2 x^{2} + 8 x + 15 = 0

x, x^{2} - 2 x - 7 = 0

(r - 3) (r + 13) = - 19

- 5 (x + 1) (x - 9) = 0

1100 - q^{2} = 300 + q^{2}

What are the solutions to the equation 12x-x^2=36 ?
The solutions to the equation 12x-x^2=36 are x=6
Find the zeros of 12x-x^2=36
The zeros of 12x-x^2=36 are x=6