What are the solutions to the equation y^2=-7y ?

The solutions to the equation y^2=-7y are y=0,y=-7

Find the zeros of y^2=-7y

The zeros of y^2=-7y are y=0,y=-7

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y^{2} = - 7 y

y = 0, y = - 7

Solution steps

y^{2} = - 7 y

Move

7 y

to the left side

y^{2} + 7 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 0 = 7

y_{1, 2} = \frac{- 7 \pm 7}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 7 + 7}{2 \cdot 1}, y_{2} = \frac{- 7 - 7}{2 \cdot 1}

y = \frac{- 7 + 7}{2 \cdot 1} : 0

y = \frac{- 7 - 7}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

y = 0, y = - 7

y^{2} = - 28

2 p^{2} + 8 p + (k + 1) = 0

3 x^{2} - 11 x - 42 = 0

n^{2} + 2 n - 120 = 0

3 x^{2} - 8 x + 16 = 0

What are the solutions to the equation y^2=-7y ?
The solutions to the equation y^2=-7y are y=0,y=-7
Find the zeros of y^2=-7y
The zeros of y^2=-7y are y=0,y=-7