What are the solutions to the equation A=7x^2-3x+10 ?

The solutions to the equation A=7x^2-3x+10 are x=(3+sqrt(28A-271))/(14),x=(3-sqrt(28A-271))/(14)

Find the zeros of A=7x^2-3x+10

The zeros of A=7x^2-3x+10 are x=(3+sqrt(28A-271))/(14),x=(3-sqrt(28A-271))/(14)

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A = 7 x^{2} - 3 x + 10

x = \frac{3 + 28 A - 271}{14}, x = \frac{3 - 28 A - 271}{14}

Solution steps

A = 7 x^{2} - 3 x + 10

Switch sides

7 x^{2} - 3 x + 10 = A

Move

A

to the left side

7 x^{2} - 3 x + 10 - A = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 7 ( 10 - A )}{2 \cdot 7}

Simplify

(- 3)^{2} - 4 \cdot 7 (10 - A) : 28 A - 271

x_{1, 2} = \frac{- ( - 3 ) \pm 28 A - 271}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 28 A - 271}{2 \cdot 7}, x_{2} = \frac{- ( - 3 ) - 28 A - 271}{2 \cdot 7}

x = \frac{- ( - 3 ) + 28 A - 271}{2 \cdot 7} : \frac{3 + 28 A - 271}{14}

x = \frac{- ( - 3 ) - 28 A - 271}{2 \cdot 7} : \frac{3 - 28 A - 271}{14}

The solutions to the quadratic equation are:

x = \frac{3 + 28 A - 271}{14}, x = \frac{3 - 28 A - 271}{14}

3 x^{2} - 16 x - 9 = 0

5 w^{2} - 30 w = 0

12 x^{2} - 58 x - 10 = 0

(v^{2} + 35) = (- 12 v - 1)

x^{2} + 33 x + 116 = 0

What are the solutions to the equation A=7x^2-3x+10 ?
The solutions to the equation A=7x^2-3x+10 are x=(3+sqrt(28A-271))/(14),x=(3-sqrt(28A-271))/(14)
Find the zeros of A=7x^2-3x+10
The zeros of A=7x^2-3x+10 are x=(3+sqrt(28A-271))/(14),x=(3-sqrt(28A-271))/(14)