What are the solutions to the equation x(x-12)=64 ?

The solutions to the equation x(x-12)=64 are x=16,x=-4

Find the zeros of x(x-12)=64

The zeros of x(x-12)=64 are x=16,x=-4

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x (x - 12) = 64

x = 16, x = - 4

Solution steps

x (x - 12) = 64

Expand

x (x - 12) : x^{2} - 12 x

x^{2} - 12 x = 64

Move

64

to the left side

x^{2} - 12 x - 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot ( - 64 )}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot (- 64) = 20

x_{1, 2} = \frac{- ( - 12 ) \pm 20}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 20}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 20}{2 \cdot 1}

x = \frac{- ( - 12 ) + 20}{2 \cdot 1} : 16

x = \frac{- ( - 12 ) - 20}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 16, x = - 4

5 x^{2} + 20 x = 0

x^{2} + 7 x = 3 x

x^{2} - 2 = 48

x^{2} - 6 x - 17 = 0

x, 1 = 3 x + 2 x^{2} y^{2}

What are the solutions to the equation x(x-12)=64 ?
The solutions to the equation x(x-12)=64 are x=16,x=-4
Find the zeros of x(x-12)=64
The zeros of x(x-12)=64 are x=16,x=-4