What are the solutions to the equation 4u^2=-5u+6 ?

The solutions to the equation 4u^2=-5u+6 are u= 3/4 ,u=-2

Find the zeros of 4u^2=-5u+6

The zeros of 4u^2=-5u+6 are u= 3/4 ,u=-2

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4 u^{2} = - 5 u + 6

u = \frac{3}{4}, u = - 2

Decimal Notation

u = 0.75, u = - 2

Solution steps

4 u^{2} = - 5 u + 6

Move

6

to the left side

4 u^{2} - 6 = - 5 u

Move

5 u

to the left side

4 u^{2} - 6 + 5 u = 0

Write in the standard form

a x^{2} + b x + c = 0

4 u^{2} + 5 u - 6 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 4 ( - 6 )}{2 \cdot 4}

5^{2} - 4 \cdot 4 (- 6) = 11

u_{1, 2} = \frac{- 5 \pm 11}{2 \cdot 4}

Separate the solutions

u_{1} = \frac{- 5 + 11}{2 \cdot 4}, u_{2} = \frac{- 5 - 11}{2 \cdot 4}

u = \frac{- 5 + 11}{2 \cdot 4} : \frac{3}{4}

u = \frac{- 5 - 11}{2 \cdot 4} : - 2

The solutions to the quadratic equation are:

u = \frac{3}{4}, u = - 2

4 x^{2} - 9 x - 6 = 0

u^{2} - 6 u

2 - x^{2} = 2 - x

\frac{x ^{2} - 1}{4} - \frac{3 x - 1}{6} = \frac{x}{2}

k^{2} + 3 k = 18

What are the solutions to the equation 4u^2=-5u+6 ?
The solutions to the equation 4u^2=-5u+6 are u= 3/4 ,u=-2
Find the zeros of 4u^2=-5u+6
The zeros of 4u^2=-5u+6 are u= 3/4 ,u=-2