What are the solutions to the equation 25=-10x-x^2 ?

The solutions to the equation 25=-10x-x^2 are x=-5

Find the zeros of 25=-10x-x^2

The zeros of 25=-10x-x^2 are x=-5

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25 = - 10 x - x^{2}

x = - 5

Solution steps

25 = - 10 x - x^{2}

Switch sides

- 10 x - x^{2} = 25

Move

25

to the left side

- 10 x - x^{2} - 25 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} - 10 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 ( - 1 ) ( - 25 )}{2 ( - 1 )}

(- 10)^{2} - 4 (- 1) (- 25) = 0

x_{1, 2} = \frac{- ( - 10 ) \pm 0}{2 ( - 1 )}

x = \frac{- ( - 10 )}{2 ( - 1 )}

\frac{- ( - 10 )}{2 ( - 1 )} = - 5

x = - 5

The solution to the quadratic equation is:

x = - 5

\frac{x ^{2}}{20} + 8 = 15

18 x^{2} - 3 x - 1 = 0

0 = 6 x^{2} - 6 x

7 + 8 x^{2} = 4 x

x^{2} + \frac{11}{2} x + \frac{9}{2} = 0

What are the solutions to the equation 25=-10x-x^2 ?
The solutions to the equation 25=-10x-x^2 are x=-5
Find the zeros of 25=-10x-x^2
The zeros of 25=-10x-x^2 are x=-5