What are the solutions to the equation 4x^2+12x=x-6 ?

The solutions to the equation 4x^2+12x=x-6 are x=-3/4 ,x=-2

Find the zeros of 4x^2+12x=x-6

The zeros of 4x^2+12x=x-6 are x=-3/4 ,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 12 x = x - 6

x = - \frac{3}{4}, x = - 2

Decimal Notation

x = - 0.75, x = - 2

Solution steps

4 x^{2} + 12 x = x - 6

Move

6

to the left side

4 x^{2} + 12 x + 6 = x

Move

x

to the left side

4 x^{2} + 11 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 4 \cdot 6}{2 \cdot 4}

1 1^{2} - 4 \cdot 4 \cdot 6 = 5

x_{1, 2} = \frac{- 11 \pm 5}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 11 + 5}{2 \cdot 4}, x_{2} = \frac{- 11 - 5}{2 \cdot 4}

x = \frac{- 11 + 5}{2 \cdot 4} : - \frac{3}{4}

x = \frac{- 11 - 5}{2 \cdot 4} : - 2

The solutions to the quadratic equation are:

x = - \frac{3}{4}, x = - 2

(2 x - 1) (x + 1) = 0

x^{2} - 5 x + 5 = 0

x^{2} = - x - 1

a^{2} + 2 a - 15 = 0

0.000006 x^{2} - 0.02 x + 25 = 85 - 0.0125 x

What are the solutions to the equation 4x^2+12x=x-6 ?
The solutions to the equation 4x^2+12x=x-6 are x=-3/4 ,x=-2
Find the zeros of 4x^2+12x=x-6
The zeros of 4x^2+12x=x-6 are x=-3/4 ,x=-2