What are the solutions to the equation 8-12x^2=0 ?

The solutions to the equation 8-12x^2=0 are x=sqrt(2/3),x=-sqrt(2/3)

Find the zeros of 8-12x^2=0

The zeros of 8-12x^2=0 are x=sqrt(2/3),x=-sqrt(2/3)

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8 - 12 x^{2} = 0

x = \frac{2}{3}, x = - \frac{2}{3}

Decimal Notation

x = 0.81649 \dots, x = - 0.81649 \dots

Solution steps

8 - 12 x^{2} = 0

Move

8

to the right side

- 12 x^{2} = - 8

Divide both sides by

- 12

x^{2} = \frac{2}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{2}{3}, x = - \frac{2}{3}

7 x^{2} + 7 x + 1 = 0

4 r^{2} + 20 r + 24 = 0

x (x + 12) = 400

x, x^{2} + 4 x y + y^{2} = 9

2 X^{2} - 6 X = 6 X^{2} - 8 X

What are the solutions to the equation 8-12x^2=0 ?
The solutions to the equation 8-12x^2=0 are x=sqrt(2/3),x=-sqrt(2/3)
Find the zeros of 8-12x^2=0
The zeros of 8-12x^2=0 are x=sqrt(2/3),x=-sqrt(2/3)