What are the solutions to the equation completesquare 7x^2+4x ?

The solutions to the equation completesquare 7x^2+4x are 7(x+2/7)^2-4/7

Find the zeros of completesquare 7x^2+4x

The zeros of completesquare 7x^2+4x are 7(x+2/7)^2-4/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

complete the square

7 x^{2} + 4 x

7 (x + \frac{2}{7})^{2} - \frac{4}{7}

Solution steps

7 x^{2} + 4 x

Write

7 x^{2} + 4 x

in the form:

x^{2} + 2 a x + a^{2}

Factor out

7

7 (x^{2} + \frac{4 x}{7})

2 a = \frac{4}{7} : a = \frac{2}{7}

Add and subtract

(\frac{2}{7})^{2}

7 (x^{2} + \frac{4 x}{7} + (\frac{2}{7})^{2} - (\frac{2}{7})^{2})

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} + \frac{4}{7} x + (\frac{2}{7})^{2} = (x + \frac{2}{7})^{2}

7 ((x + \frac{2}{7})^{2} - (\frac{2}{7})^{2})

Simplify

7 (x + \frac{2}{7})^{2} - \frac{4}{7}

1 5^{2} = x^{2} + 9^{2}

2 x^{2} + (m - 2) x + 3 = m - 3 x

x, (x - 6)^{2} + (y - 8)^{2} = k

x, x^{2} - y^{2} + 2 x y = 0

(a + 2) (2 a + 4) (2) = 5 (4) (2) + 156

What are the solutions to the equation completesquare 7x^2+4x ?
The solutions to the equation completesquare 7x^2+4x are 7(x+2/7)^2-4/7
Find the zeros of completesquare 7x^2+4x
The zeros of completesquare 7x^2+4x are 7(x+2/7)^2-4/7