What are the solutions to the equation (1-x)^2-25=0 ?

The solutions to the equation (1-x)^2-25=0 are x=-4,x=6

Find the zeros of (1-x)^2-25=0

The zeros of (1-x)^2-25=0 are x=-4,x=6

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(1 - x)^{2} - 25 = 0

x = - 4, x = 6

Solution steps

(1 - x)^{2} - 25 = 0

Move

25

to the right side

(1 - x)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

1 - x = 25 : x = - 4

Solve

1 - x = - 25 : x = 6

The solutions to the quadratic equation are:

x = - 4, x = 6

x, 4 x^{2} - y^{2} + 56 x + 2 y + 195 = 0

2 n^{2} + 10 = 8

x^{2} + 13 x + 13 = 0

c = 4900 + 500 x + \frac{x ^{2}}{2}

x, x^{2} y + y = 10

What are the solutions to the equation (1-x)^2-25=0 ?
The solutions to the equation (1-x)^2-25=0 are x=-4,x=6
Find the zeros of (1-x)^2-25=0
The zeros of (1-x)^2-25=0 are x=-4,x=6