What are the solutions to the equation completesquare x^2+4kx+(3+11k) ?

The solutions to the equation completesquare x^2+4kx+(3+11k) are (x+2k)^2+3+11k-4k^2

Find the zeros of completesquare x^2+4kx+(3+11k)

The zeros of completesquare x^2+4kx+(3+11k) are (x+2k)^2+3+11k-4k^2

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complete the square

x^{2} + 4 k x + (3 + 11 k)

(x + 2 k)^{2} + 3 + 11 k - 4 k^{2}

Solution steps

x^{2} + 4 k x + (3 + 11 k)

Complete the square using the formula:

a x^{2} + b x + c = (a x + \frac{b}{2 a})^{2} + c - \frac{b ^{2}}{4 a}

a = 1, b = 4 k, c = 3 + 11 k

(1 x + \frac{4 k}{2 1})^{2} + (3 + 11 k) - \frac{( 4 k ) ^{2}}{4 \cdot 1}

Refine

(x + 2 k)^{2} + 3 + 11 k - 4 k^{2}

(x - 2)^{2} - 7 = 5

6 x^{2} + (4 n - 3 m) x - 2 mn = 0

12 k^{2} - 19 k + 4 = 0

13 x^{2} - 7100 x - 420000 = 0

2 x^{2} - 16 x + 9 = - 10 + 9

What are the solutions to the equation completesquare x^2+4kx+(3+11k) ?
The solutions to the equation completesquare x^2+4kx+(3+11k) are (x+2k)^2+3+11k-4k^2
Find the zeros of completesquare x^2+4kx+(3+11k)
The zeros of completesquare x^2+4kx+(3+11k) are (x+2k)^2+3+11k-4k^2