What are the solutions to the equation -3x^2+12x-15=0 ?

The solutions to the equation -3x^2+12x-15=0 are x=2-i,x=2+i

Find the zeros of -3x^2+12x-15=0

The zeros of -3x^2+12x-15=0 are x=2-i,x=2+i

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- 3 x^{2} + 12 x - 15 = 0

x = 2 - i, x = 2 + i

Solution steps

- 3 x^{2} + 12 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 3 ) ( - 15 )}{2 ( - 3 )}

Simplify

1 2^{2} - 4 (- 3) (- 15) : 6 i

x_{1, 2} = \frac{- 12 \pm 6 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 12 + 6 i}{2 ( - 3 )}, x_{2} = \frac{- 12 - 6 i}{2 ( - 3 )}

x = \frac{- 12 + 6 i}{2 ( - 3 )} : 2 - i

x = \frac{- 12 - 6 i}{2 ( - 3 )} : 2 + i

The solutions to the quadratic equation are:

x = 2 - i, x = 2 + i

- 2 x^{2} - 5 = 0

9 x^{2} + 2 x = 0

- 20 v - 25 = 4 v^{2}

t^{2} - 14 t

r^{2} + r + \frac{5}{4} = 0

What are the solutions to the equation -3x^2+12x-15=0 ?
The solutions to the equation -3x^2+12x-15=0 are x=2-i,x=2+i
Find the zeros of -3x^2+12x-15=0
The zeros of -3x^2+12x-15=0 are x=2-i,x=2+i