What are the solutions to the equation -2x^2+x=6 ?

The solutions to the equation -2x^2+x=6 are x= 1/4-i(sqrt(47))/4 ,x= 1/4+i(sqrt(47))/4

Find the zeros of -2x^2+x=6

The zeros of -2x^2+x=6 are x= 1/4-i(sqrt(47))/4 ,x= 1/4+i(sqrt(47))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} + x = 6

x = \frac{1}{4} - i \frac{47}{4}, x = \frac{1}{4} + i \frac{47}{4}

Solution steps

- 2 x^{2} + x = 6

Move

6

to the left side

- 2 x^{2} + x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 2 ) ( - 6 )}{2 ( - 2 )}

Simplify

1^{2} - 4 (- 2) (- 6) : 47 i

x_{1, 2} = \frac{- 1 \pm 47 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 1 + 47 i}{2 ( - 2 )}, x_{2} = \frac{- 1 - 47 i}{2 ( - 2 )}

x = \frac{- 1 + 47 i}{2 ( - 2 )} : \frac{1}{4} - i \frac{47}{4}

x = \frac{- 1 - 47 i}{2 ( - 2 )} : \frac{1}{4} + i \frac{47}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4} - i \frac{47}{4}, x = \frac{1}{4} + i \frac{47}{4}

x, y = I n (x^{2} + 3)

4 x^{2} + 9 x + 3 = 0

X, X^{2} + Y^{2} = 0

- 6 x (x - 1) = 0

x^{2} - 39 = 0

What are the solutions to the equation -2x^2+x=6 ?
The solutions to the equation -2x^2+x=6 are x= 1/4-i(sqrt(47))/4 ,x= 1/4+i(sqrt(47))/4
Find the zeros of -2x^2+x=6
The zeros of -2x^2+x=6 are x= 1/4-i(sqrt(47))/4 ,x= 1/4+i(sqrt(47))/4