What are the solutions to the equation 11x^2-4x=-2 ?

The solutions to the equation 11x^2-4x=-2 are x= 2/11+i(3sqrt(2))/(11),x= 2/11-i(3sqrt(2))/(11)

Find the zeros of 11x^2-4x=-2

The zeros of 11x^2-4x=-2 are x= 2/11+i(3sqrt(2))/(11),x= 2/11-i(3sqrt(2))/(11)

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11 x^{2} - 4 x = - 2

x = \frac{2}{11} + i \frac{3 2}{11}, x = \frac{2}{11} - i \frac{3 2}{11}

Solution steps

11 x^{2} - 4 x = - 2

Move

2

to the left side

11 x^{2} - 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 11 \cdot 2}{2 \cdot 11}

Simplify

(- 4)^{2} - 4 \cdot 11 \cdot 2 : 62 i

x_{1, 2} = \frac{- ( - 4 ) \pm 6 2 i}{2 \cdot 11}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6 2 i}{2 \cdot 11}, x_{2} = \frac{- ( - 4 ) - 6 2 i}{2 \cdot 11}

x = \frac{- ( - 4 ) + 6 2 i}{2 \cdot 11} : \frac{2}{11} + i \frac{3 2}{11}

x = \frac{- ( - 4 ) - 6 2 i}{2 \cdot 11} : \frac{2}{11} - i \frac{3 2}{11}

The solutions to the quadratic equation are:

x = \frac{2}{11} + i \frac{3 2}{11}, x = \frac{2}{11} - i \frac{3 2}{11}

4 x - 8 x^{2} - 16 = - 16

3 x^{2} + 9 x - 13 = 0

y^{2} = 3 y + 70

x^{2} - 4 x + 5 = 0

x^{2} - 3 x - 10 = 0

What are the solutions to the equation 11x^2-4x=-2 ?
The solutions to the equation 11x^2-4x=-2 are x= 2/11+i(3sqrt(2))/(11),x= 2/11-i(3sqrt(2))/(11)
Find the zeros of 11x^2-4x=-2
The zeros of 11x^2-4x=-2 are x= 2/11+i(3sqrt(2))/(11),x= 2/11-i(3sqrt(2))/(11)