What are the solutions to the equation a^2+40a=-204 ?

The solutions to the equation a^2+40a=-204 are a=-6,a=-34

Find the zeros of a^2+40a=-204

The zeros of a^2+40a=-204 are a=-6,a=-34

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a^{2} + 40 a = - 204

a = - 6, a = - 34

Solution steps

a^{2} + 40 a = - 204

Move

204

to the left side

a^{2} + 40 a + 204 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 1 \cdot 204}{2 \cdot 1}

4 0^{2} - 4 \cdot 1 \cdot 204 = 28

a_{1, 2} = \frac{- 40 \pm 28}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 40 + 28}{2 \cdot 1}, a_{2} = \frac{- 40 - 28}{2 \cdot 1}

a = \frac{- 40 + 28}{2 \cdot 1} : - 6

a = \frac{- 40 - 28}{2 \cdot 1} : - 34

The solutions to the quadratic equation are:

a = - 6, a = - 34

x^{2} + (x + 20)^{2} = (2 x - 20)^{2}

x, 2 x^{2} - 3 y^{2} = 2 x y - 6

5 x^{2} = - 5 x + 1

\frac{1}{10} x (10 - x) - 2 = 0

3 n^{2} + 10 n = - 12 - 8 n^{2} + 10 n

What are the solutions to the equation a^2+40a=-204 ?
The solutions to the equation a^2+40a=-204 are a=-6,a=-34
Find the zeros of a^2+40a=-204
The zeros of a^2+40a=-204 are a=-6,a=-34