What are the solutions to the equation ((x+2)^2)/5+((x+2)^2)/3 = 16/3 ?

The solutions to the equation ((x+2)^2)/5+((x+2)^2)/3 = 16/3 are x=sqrt(10)-2,x=-sqrt(10)-2

Find the zeros of ((x+2)^2)/5+((x+2)^2)/3 = 16/3

The zeros of ((x+2)^2)/5+((x+2)^2)/3 = 16/3 are x=sqrt(10)-2,x=-sqrt(10)-2

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\frac{( x + 2 ) ^{2}}{5} + \frac{( x + 2 ) ^{2}}{3} = \frac{16}{3}

x = 10 - 2, x = - 10 - 2

Decimal Notation

x = 1.16227 \dots, x = - 5.16227 \dots

Solution steps

\frac{( x + 2 ) ^{2}}{5} + \frac{( x + 2 ) ^{2}}{3} = \frac{16}{3}

Multiply by LCM

8 (x + 2)^{2} = 80

Divide both sides by

8

(x + 2)^{2} = 10

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 10 : x = 10 - 2

Solve

x + 2 = - 10 : x = - 10 - 2

The solutions to the quadratic equation are:

x = 10 - 2, x = - 10 - 2

0.000006 x^{2} - 0.02 x + 25 = 10 - 0.04 x

6 p^{2} - 10 = - 57

0 = - 20 x^{2} + 360 x + 1000

45 = \frac{1}{2} (5) v^{2}

a, a^{2} = b^{2} + c^{2} - 2 b c

What are the solutions to the equation ((x+2)^2)/5+((x+2)^2)/3 = 16/3 ?
The solutions to the equation ((x+2)^2)/5+((x+2)^2)/3 = 16/3 are x=sqrt(10)-2,x=-sqrt(10)-2
Find the zeros of ((x+2)^2)/5+((x+2)^2)/3 = 16/3
The zeros of ((x+2)^2)/5+((x+2)^2)/3 = 16/3 are x=sqrt(10)-2,x=-sqrt(10)-2