What are the solutions to the equation solvefor a,a^2=b^2+c^2-2bc ?

The solutions to the equation solvefor a,a^2=b^2+c^2-2bc are a=b-c,a=-b+c

Find the zeros of solvefor a,a^2=b^2+c^2-2bc

The zeros of solvefor a,a^2=b^2+c^2-2bc are a=b-c,a=-b+c

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solve for

a, a^{2} = b^{2} + c^{2} - 2 b c

a = b - c, a = - b + c

Solution steps

a^{2} = b^{2} + c^{2} - 2 b c

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = b^{2} + c^{2} - 2 b c, a = - b^{2} + c^{2} - 2 b c

Simplify

b^{2} + c^{2} - 2 b c : b - c

Simplify

- b^{2} + c^{2} - 2 b c : - b + c

a = b - c, a = - b + c

2 a x^{2} + (2 a^{2} - a - 4) x - (2 + a^{2}) = 0

(x + 8)^{2} - 1 = 0

\frac{( x ^{2} + 4 x )}{4} = 24

n^{2} + 8 n + 12 = 0

x, 12 x^{2} - 12 x = 0

What are the solutions to the equation solvefor a,a^2=b^2+c^2-2bc ?
The solutions to the equation solvefor a,a^2=b^2+c^2-2bc are a=b-c,a=-b+c
Find the zeros of solvefor a,a^2=b^2+c^2-2bc
The zeros of solvefor a,a^2=b^2+c^2-2bc are a=b-c,a=-b+c