What are the solutions to the equation n^2+8n+12=0 ?

The solutions to the equation n^2+8n+12=0 are n=-2,n=-6

Find the zeros of n^2+8n+12=0

The zeros of n^2+8n+12=0 are n=-2,n=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

n^{2} + 8 n + 12 = 0

n = - 2, n = - 6

Solution steps

n^{2} + 8 n + 12 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 12 = 4

n_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 8 + 4}{2 \cdot 1}, n_{2} = \frac{- 8 - 4}{2 \cdot 1}

n = \frac{- 8 + 4}{2 \cdot 1} : - 2

n = \frac{- 8 - 4}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

n = - 2, n = - 6

x, 12 x^{2} - 12 x = 0

(x - 3) (x + 4) = 6

10 x^{2} + 9 = 509

a, a x + b y = 2 (a^{2} - b^{2})

3 x^{2} + 12 x = 0

What are the solutions to the equation n^2+8n+12=0 ?
The solutions to the equation n^2+8n+12=0 are n=-2,n=-6
Find the zeros of n^2+8n+12=0
The zeros of n^2+8n+12=0 are n=-2,n=-6