What are the solutions to the equation c^2+2c=0 ?

The solutions to the equation c^2+2c=0 are c=0,c=-2

Find the zeros of c^2+2c=0

The zeros of c^2+2c=0 are c=0,c=-2

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c^{2} + 2 c = 0

c = 0, c = - 2

Solution steps

c^{2} + 2 c = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 0 = 2

c_{1, 2} = \frac{- 2 \pm 2}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- 2 + 2}{2 \cdot 1}, c_{2} = \frac{- 2 - 2}{2 \cdot 1}

c = \frac{- 2 + 2}{2 \cdot 1} : 0

c = \frac{- 2 - 2}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

c = 0, c = - 2

\frac{16 !}{( 16 - 3 ) ! 3 !}

- 5 y + 2 (2 y + 1) = 2 (5 y - 1) - 7

3 x^{2} - 9 = - 156

(\frac{48 - 8 y}{12}) + 2 y = 6

\frac{5 x + 21}{4} = \frac{x}{2}

What are the solutions to the equation c^2+2c=0 ?
The solutions to the equation c^2+2c=0 are c=0,c=-2
Find the zeros of c^2+2c=0
The zeros of c^2+2c=0 are c=0,c=-2