What are the solutions to the equation 4X^2+4X+1=0 ?

The solutions to the equation 4X^2+4X+1=0 are X=-1/2

Find the zeros of 4X^2+4X+1=0

The zeros of 4X^2+4X+1=0 are X=-1/2

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4 X^{2} + 4 X + 1 = 0

X = - \frac{1}{2}

Decimal Notation

X = - 0.5

Solution steps

4 X^{2} + 4 X + 1 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

4^{2} - 4 \cdot 4 \cdot 1 = 0

X_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 4}

X = \frac{- 4}{2 \cdot 4}

\frac{- 4}{2 \cdot 4} = - \frac{1}{2}

X = - \frac{1}{2}

The solution to the quadratic equation is:

X = - \frac{1}{2}

0.5 x^{2} - 0.16 x + 0.012 = 0

(x - 12)^{2} = 18

y, x = y^{2} + 8 y + 19

x^{2} \cdot 2 = x + 3

x^{2} - 12 x - 72 = 0

What are the solutions to the equation 4X^2+4X+1=0 ?
The solutions to the equation 4X^2+4X+1=0 are X=-1/2
Find the zeros of 4X^2+4X+1=0
The zeros of 4X^2+4X+1=0 are X=-1/2