What are the solutions to the equation 12x^2-6x-18=0 ?

The solutions to the equation 12x^2-6x-18=0 are x= 3/2 ,x=-1

Find the zeros of 12x^2-6x-18=0

The zeros of 12x^2-6x-18=0 are x= 3/2 ,x=-1

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12 x^{2} - 6 x - 18 = 0

x = \frac{3}{2}, x = - 1

Decimal Notation

x = 1.5, x = - 1

Solution steps

12 x^{2} - 6 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 12 ( - 18 )}{2 \cdot 12}

(- 6)^{2} - 4 \cdot 12 (- 18) = 30

x_{1, 2} = \frac{- ( - 6 ) \pm 30}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 30}{2 \cdot 12}, x_{2} = \frac{- ( - 6 ) - 30}{2 \cdot 12}

x = \frac{- ( - 6 ) + 30}{2 \cdot 12} : \frac{3}{2}

x = \frac{- ( - 6 ) - 30}{2 \cdot 12} : - 1

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 1

- 8 x^{2} = 24

y, x^{2} + y^{2} = 3 x y

- 2 x + 72 = \frac{- x ^{2}}{12} + 36

x^{2} + 10 x + 21 = 0

2 x^{2} + 8 = 17 x

What are the solutions to the equation 12x^2-6x-18=0 ?
The solutions to the equation 12x^2-6x-18=0 are x= 3/2 ,x=-1
Find the zeros of 12x^2-6x-18=0
The zeros of 12x^2-6x-18=0 are x= 3/2 ,x=-1